The following gives a parse error. Also with 'bz, but
1'bx and 1'bz work, as do 'b0 and 'b1. Plain "a = 'bx",
without the delay, also works.
module main;
reg a;
initial
a = #1 'bx;
endmodule
Cheers,
Peter Monta pmonta@imedia.com
Imedia Corp.